How many grams of sodium bromide will be produced if 38.7 grams of sodium hydroxide was consumed in the reaction?

Answer 1

Assuming that sodium hydroxide is the limiting reagent, we would first convert 38.7 grams of NaOH to moles, then through stoichiometry we can convert the moles back to grams of NaBr.

38.7 g NaOH X (1 mol NaOH/40 g NaOH) = 0.968 mol NaOH

0.968 mol NaOH (1 mol NaBr/1 mol NaOH) = 0.968 mol NaBr

0.968 mol NaBr (103 g NaBr/1 mol NaBr) = 99.7 g NaBr