Write an equation of a line that passes through the point (-12, -2) and is perpendicular to y = -3/7x - 5

Question

Hope y'all can help me answer this.

Answer 1

First, find the slope of the line that is perpendicular to y=(-3/7)x-5, (which is the negative reciprocal of -3/7). So, the new slope is 7/3.

Next, substitute the value of the new slope and the given point (-12,-2) to y=mx+b to find b.

-2=(7/3)(-12)+b

-2=-28+b

b=26

Finally, write the equation of the new line in y=Mx+b format with m=7/3 and b=26.

Answer: y=(7/3)x+26