Mass and percent yield?

Question

Pinacol rearrangement experiment:

Measured benzopinacol (start) = 0.502 g

Collected solid (end) = 0.480 g

What would the start and final mass be in mol?

What would the percent yield be?

Answer 1

To find moles, we need to know the molar mass of the compound in question. A quick search tells me the molar mass of benzopinacol is 366.4g/mol

We don't know the experiment that was conducted, so we don't know the starting materials, nor do we know the products formed. Hence we cannot determine the percent yield. Was this the synthesis of benzopinacol, or was it a reaction using benzopinzcol as a reactant? What is the nature of the collected solid at the end? Is it benzopinacol? I don't think so, but can't be sure as you haven't provided sufficient detials.

0.502 g benzopinacol x 1 mol / 366.4 g = 0.00137 moles benzopinacol