solve the system

Question

x=,y=,z=

Answer 1

use substitution, elimination or matrix algebra

(x,y,z) = (191/90, -39./20, 53/180)

-4x-2y+2z=-4

x+y+13z=4

12x+13y+3z= 1

-2x -y + z =-2

2x +2y +26z = 8

add to get

y +27z = 6

12x +12y + 156z = 48

12x +13y + 3z = 1

subtract to get

y -153z = -47

y+27z = 6

-180z = -53

z = 53/180

y = 6-27(53)/180 = 6 -3(53)/20 = 120/20 - 159/20 = -39/20

y =-39/20

x = 4-y-13z = 4+39/20 -13(53)/180 = 119(9)/180 -13(53)/180= 1071/180-689/180

= 382/180

x=191/90

check the answers plug the x,y and z values into each of the 3 original equations