Raymond B. answered 05/26/23
Math, microeconomics or criminal justice
t=5a
p=2a
m=2p=4a
t+a+p+m= 11
(5+1+2+4)a=11
a=11/12 lb of amberjack
t=55/12 lb of tuna
p=22/12 lbs of tarpon
m=44/12 lbs of marlin
Sarah S.
asked 09/28/21he crew on a fishing boat caught four fish that weighed a total of 1,164 pounds. The tarpon weighed twice as much as the amberjack and the white marlin weighed twice as much as the tarpon. The weight of the tuna was 5 times the weight of the amberjack.
How much did each fish weigh?
Raymond B. answered 05/26/23
Math, microeconomics or criminal justice
t=5a
p=2a
m=2p=4a
t+a+p+m= 11
(5+1+2+4)a=11
a=11/12 lb of amberjack
t=55/12 lb of tuna
p=22/12 lbs of tarpon
m=44/12 lbs of marlin
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