Touba M. answered 09/28/21
B.S. in Mathematics with 20+ years of Teaching and Tutoring Experience
Hi,
y^2 + xy - 3x = 14,
First, you need to know:
(y2)' = 2yy'
(xy)' = x'y + y'x ( rule of product)
(3x)' = 3x'
Second, derivative of y^2 + xy - 3x = 14 ======> 2yy' + x'y + y'x - 3x' = 0 I
Third, replace given information to the equation # I
y'=dy/dt = -4 when x = -2 and y = -2
2(-2)(-4) + x' (-2) + (-4)(-2) - 3x'=0 ======> dx/dt = x' = 24/5
I hope it is useful,
Minoo