Without using​ point-slope form, find the​ slope-intercept form of the line that has slope m = 4 and passes through the point (1, -13)

Answer 1

slope intercept form is y=mx+b

m given as 4

also given (1,-13) on line, 1 is x value, -13 y value

substutute

-13=4*1+b

b=-17

also could see since b is y oordinate when x=o

that going back one unit x from (1,-13) will be point (0,-17)

since one back is four down if slope is 4

(same as one unit forward is four up if slope is 4)

find same result b=-17

so y=4x-17 is equation of line.

Answer 2

(1,-13) with slope = 4

plot the point, draw a line roughly with slope 4 through the point, back down to where it intersects the y axis.

you'll have to go left 1 and down 4 getting to the point (0,-17)

y=mx+b where m= the slope and b = y-intercept

y=4x -17 is the equation with slope 4 and intercept -17 through the point (1,-13)

or just plug in the numbers 4 for m and 1 for x and -13 for y into

y=mx+b

-13=4(1)+b

b =-13-4 =-17

y=4x-17