Solve the following system of equations algebraically.

Question

y = x² - 10x + 28

2x - y = 4

Answer 1

2x - 4 = x² - 10x + 28; x²- 12x + 32 = 0; (x - 4)(x - 8) = 0; x = 4 or x = 8

x = 4, y = 4; x = 8, y = 12

Solutions: (4, 4); (8, 12)