math homework please help

Question

Find the slope of the graph of the function at the given point.

f(x)=√₁-x³, (-2, 3)

f '(−2) = __?

Answer 1

f(x) = sqr(1-x^3) point is (-2,3)

f(-2) = sqr(1+8) = sqr9 = 3

take the derivative

f'(x) = .5(-3x^2)/sqr(1-x^3)

f'(-2) = .5(-3(4))/sqr(1+8) = -6/3 = -2 = slope at the given point