Find the equation of the line that contains the point (4,-2) and is perpendicular to the line y=-2x+5

Answer 1

y+2 = (1/2)(x-4)

y= x/2 -2-2

y =x/2 -4 is the equation of the perpendicular line through the given point, in slope intercept form

or

2y = x -8

or

x-2y= 8 if you want to remove fractions and negative signs

check the answer by plugging in the point (4,-2)

4-2(-2) = 4+4 = 8

a perpendicular line has slope = negative inverse of the given line

the negative inverse of -2 is 1/2

just change the sign and flip the fraction upside down to get the negative inverse

-2/1 becomes +1/2

when an equation is solved for y, the slope is the coefficient of the x term