Let's call the point 3/10 of the way between A and B point C. Point C has coordinates (xC,yC) as follows:
xC = xA + (3/10)(xB-xA)
yC = yA + (3/10)(yB-yA)
Plug in the numbers and compute the answers.
Let's call the point 3/10 of the way between A and B point C. Point C has coordinates (xC,yC) as follows:
xC = xA + (3/10)(xB-xA)
yC = yA + (3/10)(yB-yA)
Plug in the numbers and compute the answers.
Michael M. answered 09/22/21
Math, Chem, Physics, Tutoring with Michael ("800" SAT math)
The point is 3/10 from A and 7/10 from B so use this method, which is basically a weighted average of the two endpoints.
M = 7/10 * A + 3/10 * B
Notices that the 7/10 is multiplied by A even though the point is 3/10 away from A and similarly 3/10 is multiplied by B even though the point is 7/10 away from B
Now we'll plug in
M = 7/10 * (-3, -8) + 3/10 * (11, 7)
The x-coordinate is 7/10 * (-3) + 3/10 * 11 = -21/10 + 33/10 = 12/10 = 1.2
The y-coordinate is 7/10 * (-8) + 3/10 * 7 = -56/10 + 21/10 = -35/10 = -3.5
Thus the point M is (1.2, -3.5)
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