Raymond B. answered 05/29/23
Tutor
5
(2)
Math, microeconomics or criminal justice
L=2w-2
P=32 inches = 2(L+w)
16 = L+w = 2w-2+w = 3w-2
3w = 18
w = 6 inches wide
L = 10 inches Long
Jorge A.
asked 09/21/21The perimeter of a rectangle is 32 inches. The length of the rectangle is 2 inches less than 2 times the width. Find the width and the length of the rectangle.
Raymond B. answered 05/29/23
Math, microeconomics or criminal justice
L=2w-2
P=32 inches = 2(L+w)
16 = L+w = 2w-2+w = 3w-2
3w = 18
w = 6 inches wide
L = 10 inches Long
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