Mean of 82 and a standard deviation of 4 what percentage of students scored between a 83 and 94 on their test

Answer 1

a little less than 50%

z scores are (83-82)/4 = 1/4 = .25

and (94-82)/4 = 12/4 = 3

from 0 to 3 is 99.7%/2 = 49.85%

subtract the percentage from 0 to .25

and it's maybe 40% or so

use a z calculator or z tables