How much of a(n)60% orange juice drink must be mixed with 5 gallons of 10% orange juice drink to obtain a mixture that is 50% orange juice?

Answer 1

How much of a(n)60% orange juice drink must be mixed with 5 gallons of 10% orange juice drink to obtain a mixture that is 50% orange juice?

Volume: Xvolume of 60% + 5gallons = X + 5

%Mix: X(0.60) + 5(0.10) = (X + 5)(0.50)

Solve for X:

0.60X + 0.50 = 0.50X + 2.50

0.10X = 2.00

X = 20

Answer: Mix 20 gallons of the 60% solution with 5 of the 10% to get 25 gallons of 50%.