Suppose that x is the length and y the width. We have the relations x=2y-5 and 2x+2y=50. Thus, 4y-10+2y=50 or 6y=60 or y=10 and x=15.
RTDTR V.
asked 09/17/21The length of a rectangle is five centimeters less than twice its width. If the perimeter of the rectangle is 50 centimeters, find the dimensions.
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