Find two consecutive even integers such that the sum of the integers is equal to 32 less than 5 times the larger integer.

Question

i need the answer quickly...

Answer 1

Let the smaller even number be X.

Then the bigger even number is X + 2.

The sum of the two numbers is

X + X + 2

We are told in the question the above sum is 5(X+2) - 32.

Therefore,

X + X + 2 = 5 ( X + 2 ) - 32

2X + 2 = 5X + 10 - 32

2X + 2 = 5X - 22

+2 + 22 = 5X - 2X

24 = 3 X

3X = 24

X = 8

The two consecutive even numbers are 8 and 10.

Hope this helps.