3(d-8)-5=9(d+2)+1

Answer 1

Hello,

I am assuming you want to solve for the value of d.

3(d-8)-5=9(d+2)+1

First, we should use the distributive property to spread the 3 across the (d - 8) and to spread the 9 across the (d + 2). This will give us:

(3d - 24) - 5 =(9d + 18) + 1

Next, we can add like terms on the left side of the equal sign and on the right side of the equal sign.

3d - 29 = 9d + 19

Add 29 to both sides.

3d = 9d + 48

Subtract 9d from both sides.

-6d = 48

Divide both sides by -6 and then reduce the fraction.

d = 48/(-6)

d = -8

:)