Please help with problems

Question

(3/8p^3-5/7p^2-2/5)-(5/8p^3-2/7p^2+7/5)

Answer 1

(3/8p³ - 5/7p² - 2/5) - (5/8p³ - 2/7p² + 7/5)

Make sure you distribute the negative to all the terms in the second parentheses:

3/8p³ - 5/7p² - 2/5 - 5/8p³ + 2/7p² - 7/5

Then combine like terms:

(3/8p³ - 5/8p³) + (-5/7p² + 2/7p²) + (- 2/5 - 7/5)

(-2/8p³) + (-3/7p²) + (-9/5)

Reduce fractions that need to be reduced:

-1/4p³ - 3/7p² - 9/5

Answer 2

(3/8p^3-5/7p^2-2/5)-(5/8p^3-2/7p^2+7/5)

= 3/8p^3-5/7p^2-2/5-5/8p^3+2/7p^2-7/5

= 3/8p^3-5/8p^3-5/7p^2+2/7p^2-2/5-7/5

= (3/8-5/8)p^3+(-5/7+2/7)p^2+(-2/5-7/5)

= -1/4p^3-3/7p^2-9/5