A board, 68 cm long is cut into three pieces such that the second piece is twice as long as the first and the third is 3 cm longer than the second. Find the length of the shortest piece.

Answer 1

Hello Kailee.

Since second piece is twice as long as first;

length of first piece: x

length of second piece: 2x

length of a third piece: 2x +3

when you add them you get 68;

x+2x+2x+3 = 68

5x+3 = 68

5x =65

x = 13

hope that helps