Robert J. answered • 03/18/13
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work
= ∫F(x,y) ⋅ dr
= ∫2dx + xdy
= ∫[0, 1] (2 + 2x^2)dx, since dy = 2xdx
= 8/3
Sun K.
asked • 03/18/13Compute the work done?
Compute the work done by the force field F(x, y)=<2, x> where C is the portion of y=x^2 from (0, 0) to (1, 1).
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Sun K.
But what's dx?
03/18/13