Please help pls psl

Question

Two torpedoes 3450 km apart, are launched at the same time and are headed towards each other. They collide after 2 hours. The average speed of one torpedo is twice that of the other. What is the average speed of each torpedo?

Answer 1

d= rt

distance = rate of speed times time

r = speed of the slower torpedo, 2r = speed of the faster torpedo

d = r(2) + 2r(2) distance = speed times 2 hours

d =2(r+2r) = 2(3r) = 6r

r = d/6 = 3450/6 = 575 km per hour = speed of the slower torpedo

2r = 1150 km per hour = speed of the faster torpedo

in 2 hours the slower torpedo travels 2 x 575 = 1150 km

in 2 hours the faster torpedo travels 2 x 1150 = 2300 km

1150 + 2300 = 3450 km