Raymond B. answered 08/26/21
Math, microeconomics or criminal justice
t = 20 km
k=15 km
T=K+1 measured in hours, T= Tad's time, K=Ken's time
distance = rate of speed times time
d=rh
r = d/h
rate of speed is the same for both Tad and Ken
r=d/h = 20/T = 15/K
20/(K+1) = 15/K
cross multiply
20K = 15K +15
5K =15
K =3 hours
T = 4 hours
It takes Ken 3 hours to get to school
going 15 km at 5 km per hour
5(.62) = about 3.1 miles per hour
average normal walking speed is 5 mph
Ken is riding his bike so slowly, he'd be better off walking