Math Question (Help Please!!)

Question

Two torpedoes 3450 km apart, are launched at the same time and are headed towards each other. They collide after 2 hours. The average speed of one torpedo is twice that of the other. What is the average speed of each torpedo?

Answer 1

F=2S the faster torpedo has speed twice the slower torpedo

d=rt = 3450 =r2

distance = rate of speed times time

r= 3450/2 = 1725 km per hour = average speeds of the two torpedoes added together

3450 = 2F + 2S = 2(2S) + 2S = 6S

S = 3450/6 = 575 km per hour for the slower torpedo

F =2S = 1150 km per hour for the fast torpedo

F+S = 1150+575 = 1725

1725 times 2 hours = 3450

in 2 hours the slower torpedo traveled 1150 km

in 2 hours the faster torpedo traveled 2300 km

total distance of both added together = 3450