
Yinyan W.
asked 08/11/21math help, the given series is absolutely convergent, conditionally convergent or divergent:
Determine whether the given series is absolutely convergent, conditionally convergent or
divergent:
∑(-1)^n ln((n)^2)/ln^(2)(n)
from n = 2 to infinity
1 Expert Answer

Yefim S. answered 08/11/21
Math Tutor with Experience
∑n=2∞(-1)nln(n2)/(ln2n).
- lim n→∞In(n2)/(ln2n) = lim n→∞ 2/lnn = 0;
- ln(n + 1)2/ln2(n + 1) = 2/ln(n + 1) < 2/lnn = lnn2/ln2.
So, by alternative series test our test convergent.
But absolute values series ∑n=2∞ln(n2)/(ln2n)diverges becouse by comparison test ln(n2)/ln2n = 2/lnn > 2/n
and series .∑n=2∞2/n diverges.
So, given series converges conditionally.
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Adam B.
08/11/21