what os the rate of the swift in calm air and rate of the wind ;

Question

The bird capable of the fastest flying speed is the swift. A swift flying with the wind to a favorite feeding spot traveled 36 mi in 0.3 h. On returning, now against the wind, the swift was able to travel only 33 mi in the same amount of time. What is the rate of the swift in calm air, and what was the rate of the wind?

Answer 1

36 miles in .3 hours with the wind

33 miles in .3 hours against the wind

distance = rate of speed times time

d = rt

d = (r+w)t

d= (r-w)t

36 = (r+w)(.3) with the wind

33 = (r-w)(.3) against the wind

36 = .3r + .3w

33 = .3r -.3w

add the two above equations to eliminate one variable

69 = .6r

r = 69/.6 = 115 miles per hour = bird speed

w=(.3r-33)/.3 = (.3(115)-33)/.3 = 34.5-33)/.3=1.5/.3=5 mph =wind speed

115+5 = 120. 120(.3) = 36 miles with the wind

115-5 = 110 110(.3) = 33 miles against the wind