Write an equation of the line that passes through (-2,3) and (0,8)

Question

Kinda stuck need help on this problem.

Answer 1

Another way, once you've figured out the slope as Mahmut showed you...

y = mx + b

I'll use the other point, just for fun.

3 = (5/2)(-2) + b

3 = -5 + b

b = 8

y = (5/2)x + 8

Answer 2

Hello Isabel.

When you create an equation from 2 points; you need to find a slope first then you can use any of the points to follow "point-slope form"

slope is (y₂ - y₁)/(x₂ - x₁) = (8-3)/(0--2) =5/2;

lets chose point (0, 8) and apply point-slope form;

y - 8 = 5/2 *(x -0)

y -8 = 5x/2

y = 5x/2 +8

hope that helps

Answer 3

(-2,3) and (0,8) have a line through them with a y intercept of 8= b, and slope = (8-3)/(0--2) = 5/2= m

y=mx+b is the general form of a line in slope intercept form

m=5/2, b= 8

y =(5/2)x + 8

or to eliminate fractions, multiply by 2

to get 2y=5x + 16

or 2y -5x = 16