Write an equation in slope-intercept form of the line that passes through (-2,5) and (-4,-5)

Question

kinda stuck need help on this problem

Answer 1

Equation of a Line in Slope-intercept Form:

y = mx + b

Slope:

m =( y₁ - y₂₎ / (x₁ - x₂)

In this example, slope:

m = (5 - (-5)) / (-2 - (-4))

m = (5 + 5) / (-2 + 4)

m = 10 / 2

m = 5

Y-intercept:

Plug in one of the points (-2, 5), and the slope, in the Slope-intercept Form to find the "intercept":

y = mx + b

5 = 5 (-2) + b

5 = -10 + b

5 + 10 = b

b = 15

Plug in the slope and the intercept to find the Equation of the Line in Slope-intercept Form:

y = 5x + 15

Answer 2

Cool, here goes.

1) to find the slope of a line that passes through points (x₁, y₁) and (x₂, y₂), all you have to do is take the change in y and divide it by the change in x. In other words, (y₂ - y₁) / (x₂ - x₁) = m.

2) Now that you have the slope, you can find the intercept. This is the point where x = 0, and the b of

y = mx + b. To find this, you plug in one of the points you know already, let's say (x₁, y₁), and solve for b.

y = mx + b --> y₁ = mx₁ + b --> y₁ - mx₁ = b.

I hope this clears things up a bit. If not, or if you need more help in algebra, I invite you to reach out! We'll see if we can work out either a one-off or series of lessons to get you right on track. Best!

-Miles