Write an equation in slope-intercept form of the line that passes through (-4,-1) and (8,-4).

Question

kinda stuck need help on this problem

Answer 1

First find the slope between the two points by using the slope formula. m = (y2-y1)/(x2-x1) = (-1 - (-4))/ (-4-8) = 3/(-12) = -1/4 So the slope is -1/4. Now we need to find the y-intercept. We will do this by putting the one of the points and the slope into the point-slope form of a linear equation which is y2-y1 = m(x2-x1). Let’s plug in the point (8,-4). So we get y-(-4) = (-1/4)(x-8) —> y+4 = (-1/4)x + 2 —> y = (-1/4)x - 2. So y = (-1/4)x - 2 is our final answer.

Answer 2

Determine the slope by m = [Y2-Y1/ X2-X1] , -4 - -1/ 8- -4 = -3/12 = -1/4 . The use the point slope form the write the equation for the line; Y-Y1 = m(X-X1), and rearrange to the Y-intercept form; Y = Mx + b

Y -1 = -1/4(X - -4) —> Y - 1 = -1/4x +1 —> y = -1/4x + 2

Answer 3

y=-x/4 +2 is the equation through the two given points

find the slope

= m = the difference in y coordinates over x coordinates = rise over run = (-4+1)/(8+4) = -3/12 =- 1/4

y=mx +b

y = (-1/4)x + b = -x/4 + b

plug in either point to solve for b

y=-x/4 + b

-4 = -8/4 + b

b =-4 +2 = -2

b =-2

y= -x/4 -2