
Isaiah W.
asked 07/27/21Find the sum of the equation
Find the sum.
(a) 1 |
3 |
+ 2 |
32 |
+ 22 |
33 |
+ 23 |
34 |
+ ![]() |
310 |
S =
(b) 1 + 1 |
21/2 |
+ 1 |
2 |
+ 1 |
23/2 |
+
S =
1 Expert Answer
The first sequence is:
20·31 + 21·32 + 22·33 + ... + 29·310
Each term is of the form 2n-1·3n. You can write this as 2n-1·3n-1·3 = 3·6n-1
which is a standard geometric sequence. Use the summation formula for a geometric sequence to find the answer.
Sum = a·(1-rn) / (1-r)
where a = 3 and r = 6 and n = 10.
-------
The second sequence has the form:
1·2(n-1)/2
which is geometric. Use the geometric summation formula given above to find the sum when a = 1, r = 2, n = 4.
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Joanie L.
Please try and repost your question without the table. Try posting each part of your question on a single line so that it's easier to read.07/27/21