Sum of the numbers

Question

the sum of the 3 numbers is 110 the second number is 10 more then the first and the third is 3 times more then the second

Answer 1

x+y+z + 110

y=10+x or x=y-10

z= 3y

y-10 + y + 3y = 110

5y = 120

y = 24 = the 2nd number

z = 3(24) = 72 = the 3rd number

x=24-10 = 14 = the 1st number

14 +24 + 72 = 110