Raymond B. answered 07/26/21
Math, microeconomics or criminal justice
f(x) = 1.08208e^.3387x
8.6 = 1.08208e^.3387x
8.6/1.08208 = e^.3387x
lin(8.6/1.08208) = .3387x
x = ln(8.6/1.08208)/.3387 = 23.47 + 1998 = 2021.47 = about May 2022
Colton S.
asked 07/26/21QUESTION #1
The value of China's exports of automobiles and parts (in billions of dollars) is approximately f(x)=1.8208e0.3387x, where x = 0 corresponds to 1998. In what year did/will the exports reach $8.6 billion?
QUESTION #2
According to the U.S. Census Bureau, the population of the United States in 2008 was 304 million people. In addition, the population of the United States was growing at a rate of 1.1% per year. Assuming this growth rate is continues, the model
P(t)=304⋅(1.011)t−2008represents the population P (in millions of people) in year t.
According to the model, when will the population be 419 million people? Be sure to round your answer to the nearest whole year.
QUESTION #3
The value of a car is depreciating according to the model
V=9000(0.82)t , where V is the value of the car t years after purchase.
Solve, using logarithms, for when the value of the car will reach $6,000. Give your answer to the nearest tenth.
Raymond B. answered 07/26/21
Math, microeconomics or criminal justice
f(x) = 1.08208e^.3387x
8.6 = 1.08208e^.3387x
8.6/1.08208 = e^.3387x
lin(8.6/1.08208) = .3387x
x = ln(8.6/1.08208)/.3387 = 23.47 + 1998 = 2021.47 = about May 2022
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.