
Bradford T. answered 07/26/21
Retired Engineer / Upper level math instructor
Let b = barrels if oil, s = speed, d = distance
b = kds2
when b = 250, d = 500 and s = 48
250 = k(500)482
k = 1/(2(48)2)
when d = 480 and s = 24
b = (1/(2(48)2))480(24)2 = (480/2)(24/48)2 = 240(1/4) = 60 barrels