Solve this equation for 0° ≤ 𝜃 ≤ 360°. 2𝑐𝑜𝑠𝑥 − √3 = 0

Answer 1

The first parameter of this problem tells us we're going around our unit circle just once, so we can't have values of x greater than 2π or less than 0π. The given equation can be simplified using these steps:

2cosx -√3 = 0

2cosx = √3

cosx = √3/2

Now we just have to look at our unit circle and figure out which x values equal √3/2. Hopefully you'll notice that cosx = √3/2 at π/6 and 11π/6 (a.k.a. 30º and 330º). You can also plug this into your calculator:

x = cos^-1(√3/2). However, you'll only get 1 answer from that - 30° or π/6. Be careful when using calculator simplification.