By Gaussian elimination, the row echelon form is
1 2 -3 -3
0 1 7 1
0 0 -12 0
Which gives x=-5, y =1 and z =0.
If you do not know how to do Gaussian elimination to get the row echelon form, make a comment and I will try to help further.
Isaiah W.
asked 07/22/21Solve the system of linear equations. (If the system is dependent, express your answer in terms of t, where x = x(t),
y = y(t),
and z = t.
If the system is inconsistent, enter INCONSISTENT.)
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x | + | 2y | − | 3z | = | −3 |
| −2x | − | 4y | − | 6z | = | 6 | |
| 3x | + | 7y | − | 2z | = | −8 | |
(x, y, z) =
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By Gaussian elimination, the row echelon form is
1 2 -3 -3
0 1 7 1
0 0 -12 0
Which gives x=-5, y =1 and z =0.
If you do not know how to do Gaussian elimination to get the row echelon form, make a comment and I will try to help further.
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