Can someone please help me with this Geometry problem?

Question

Find the area of △ABC with vertices at A (2,-3), B (0,1), and C (0,-2).

For this I got 6, am I correct?

Answer 1

Hello, Jesset.

First you can use the distance formula to find each sides (a= √(x2−x1)^2+(y2−y1)^2)

then you can use Heron's formula: √s(s−a)(s−b)(s−c)

Where s Is the semi perimeter. ((𝑠=𝑎+𝑏+𝑐)/2)

Hope that helps

Answer 2

The answer should be 3.

area of ABC=1/2*3*2=2(Thinking BC=3 as base, height will be 2)