Math interest problem

Question

Joe invests a total of $4000 in two plans.

Part of the money is invested at 8% per year

and the rest at 11% per year. The interest

paid after 1 year on the 11% investment is

$212 more than the interest paid on the 8%

investment. How much did Joe invest in

each?

Answer 1

.11(4000-X) = 212 + .08X

.11(4000) - .11X = 212 + .08X

440 -212 = .08X +.11X

.19X = 228

X = 228/.19 = $1,200 invested at 8%

4000-1200 = $28,000 invested at 11%