Jaylen A.

asked • 07/18/21# Take a factor out of the square root:

√48x^2, where x**≤0**

## 2 Answers By Expert Tutors

x comes out, as x^2 = x^2

48 is 16 x 3, so 4 comes out 16 is a perfect square. 4^2 = 16

leaving only 3 inside the radical

4xsqr3 = sqr(48x^2)

the constraint x is less than or equal to zero doesn't seem to make any difference

when you square x it's the same value whether x is negative or positive

factor out an x will make 4xsqr3 negative

so add in 4xsqr3 < 0 or = 0

Mahmut S. answered • 07/18/21

SAT Math Expert

First you need to find perfect square factors of 48

Check some factors of 48;

2*24. nope

3*16 yes because 16 is perfect square and 3 is prime so

√48 = √16*√3 = 4√3

we had also √x^2 = x

answer is 4x√3

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Mahmut S.

If you need any explanation of any part, please let me know we can do some similar examples together07/18/21