bh/2
2x2 - 3x - 20
2(-20) = -40, so we need two factors of -40 whose sum is -3
2x2 - 3x - 20 = 2x2 - 8x + 5x - 20 = 2x(x - 4) + 5(x - 4) = (2x + 5)(x - 4)
Ini A.
asked 07/15/21bh/2
2x2 - 3x - 20
2(-20) = -40, so we need two factors of -40 whose sum is -3
2x2 - 3x - 20 = 2x2 - 8x + 5x - 20 = 2x(x - 4) + 5(x - 4) = (2x + 5)(x - 4)
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