I am very lost on how to solve this: Grade 12 chemistry

Question

In the following reaction, the initial rate of production of N₂O gas is 0.51 mol/(L*s)

What is the rate of loss of NO

3NO_(g) ---> N₂O_(g) + NO_2(g)

Answer 1

As the balanced equation shows, for every molecule of N2O produced, 3 molecules of NO must be used. In that case the rate of loss of NO should be 3 times the rate of production of N2O. So, 3 x 0.51 = 1.53 moles/L*s