State the domain and range of y=sqrt(x-3). Is this a function?

Answer 1

y = sqr(x-3) = the top half of y^2 = x-3 x must be greater or equal to 3, domain is x> 3

range is any non-negative number y> 0

It's a function because it passes the vertical line test. As it's only the top half of a rightward opening parabola, there is only one y value for a given x value.

Had both square roots been in the equation, y= + or - sqr(x-3) it would not be a function.

square root means the + square root, unless indicated otherwise.