Brittany K.
asked 07/13/21
Find the dimensions of a rectangle with a perimeter of 48 cm if the length is 8 cm less than three times the width
Raymond B.
answered 07/13/21
Math, microeconomics or criminal justice
L = 3W-8
P= 2(L+W) = 2(3W-8 + W) = 2(4W-8) = 8W-16 = 48
8W-16 = 48
8W = 48+16 =64
W = 64/8 = 8 cm wide
L= 3(8)-8 = 16 cm long
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