Im not sure how to plug this into a formula

Question

Determine the quadratic function that has the given roots and passes through the given point. Express each function in standard form a. 𝑥 = 2 ± √5, 𝐺𝑖𝑣𝑒𝑛 𝑃𝑜𝑖𝑛𝑡: (2,10) [5 T/I] b. 𝑥 = 1 3 𝑎𝑛𝑑 𝑥 = −4, 𝐺𝑖𝑣𝑒𝑛 𝑃𝑜𝑖𝑛𝑡: (1,5) [5 T/I]

Answer 1

y=-2(x-2)^2 + 10

has vertex at the given point (x,10)

when y=0 = -2(x-2)^2 +10

(x-2)^2 = 10/2 = 5

x-2 = + or - sqr5

x = 2 + or - sqr5 are the roots, zeros, or x intercept

It's a downward opening parabola, axis of symmetry is x=2