Bring the fraction:

Question

b/7a^2c to a denominator of 35a^3c^3

a/a-4 to a denominator of 16-a^2

Answer 1

b/7a^2c with denominator of 35a^3c^3

is 5abc^2/35a^3c^3

a/(a-4) with denominator 16-a^2

which = (4-a)(4+a)=-(a-4)(a+4))

is -(4+a)a/(16-a^2) = -(a^2+4)/(16-a^2)