Raymond B. answered 07/08/21
Math, microeconomics or criminal justice
65 = S+A
2300 = 30A + 40S
65(30)= 30A + 30S
2300-1950 = 10S
S = 350/10 = 35 same day tickets
A = 65-35 = 30 advance tickets
30(30) + 40(35) = 900 = 1400 = 2300
Marea M.
asked 07/08/21Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $30 and same-day tickets cost $40, For one performance, there were 65 tickets sold in all, and the total amount paid for them was $2300. How many tickets of each type were sold?
Raymond B. answered 07/08/21
Math, microeconomics or criminal justice
65 = S+A
2300 = 30A + 40S
65(30)= 30A + 30S
2300-1950 = 10S
S = 350/10 = 35 same day tickets
A = 65-35 = 30 advance tickets
30(30) + 40(35) = 900 = 1400 = 2300
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