Raymond B. answered 07/07/21
Math, microeconomics or criminal justice
f(x) = sqr(x)
g(x) = 6x^2 -7
(fog)(x) = f(g(x))
f(g(x)) = f(6x^2-7) = sqr(1/6x^2-7)
another possibility is
f(x)= x^2
and
g(x) = (6x^2-7)^(1/4)
and there's an infinite number of other f and g's