What is the equation of the line that passes through the point(-3,2) and has a slope of "-3"

Question

PLEASE HELP!!!!!!!!!!!!!

Answer 1

slope = -3 = (y-2)/(x+3)

y-2 = -3x -9

y = -3x -9 +2

y =-3x -7 is the equation of a line with slope -3 through the point (-3,2)

Answer 2

Hello,

You can solve this equation with the the point-slope intercept form,

y- y1 =m (x - x1)

You can substitute the known variables into the equation and simplify the equation until it is in a slop=intercept form, y = mx+b

Hope that helps!

Answer 3

Using point-slope form

y - y₁ = m(x - x₁)

where y₁ and x₁ are the points on a line and m is the slope, we can plug in our numbers to get

y - 2 = -3(x - (-3))

simplified is

y - 2 = -3(x + 3)