The sum of three real numbers

Question

the sum of numbers is 110 the second number is 5 less than the first. the third number is times the second

Answer 1

S =F-5, F=S+5

T = aS "third number is times the second" You're missing a word, call it "a"

F+S+T = 110

S+5 + S + aS = 110

(2+a)S = 110-5 = 105

S = 105/(2+a) IF "a" were 3 then S= 105/5 = 21

T =aS = 3(21) = 63

F= S+5 = 26

Sum of all three is: 21 +63 +26 = 110