What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –Two-thirds(x – 6) and passes through the point (−2, −2)?

Answer 1

find the slope of the given equation

y-4= -2/3(x-6)

y-4= (-2x)/3+4

y=(-2x)/3+8

the slope of the line perpendicular to y, is the negative reciprocal

m= 3/2

y-(-2)=3/2(x-(-2))

y+2=(3x)/2+3

y= (3x)/2+1