Jeanie K. answered 06/24/21
Boston University Grad for Math Tutoring
You can first use the point-slope equation of the line, which is y-y1 = m(x-x1), where (x1, y1) is the point given and m is the slope. Plugging in the information given, y-5 = 0(x-8), which gives y-5=0. Putting this in slope-intercept form gives y=5. Hope this helps!
David W.
slope-intercept form is y = mx+b, where m=slope. slope=0 and use point gives y = 0(8) + 5. That leaves y=5.06/24/21