Algebra I Question, Help Needed

Question

Solve the equation: (x+2)(3x+4)=0 

Solve the equation: 3(x+4)²= 75

Answer 1

Answer :

(x + 2 )(3x + 4) => x = - 2 ; x = -4/3

3( x + 4)² = 75 => x = 1 , x = - 9

Explanation :

(x+2)(3x+4)=0 

=> (x + 2 ) = 0 and ( 3x+ 4) = 0

=> x = - 2 and 3x = - 4

=> x = - 2 and x = - 4 / 3

3(x+4)²= 75

=> (3/3) ( x + 4)² = 75/3

=> ( x + 4) ² = 25

=> (x + 4) = 25^(1/2)

=> x + 4 = + 5 , and x + 4 = - 5

=> x = 5 - 4 , and x = - 5 - 4

=> x = 1 , and x = - 9

Answer 2

(x+2)(3x+4) = 0 just set each factor = 0

x+2 =0

x =-2

3x +4 =0

3x =-4

x =-4/3

3(x+4)^2 = 75 divide by 3

(x+4)^2 = 25 take the square root of both sides

x+4 = + or - 5

x+4 =5 x+4 =-5

x =1 x=-9